log8(x+7)=log8(2x-15) log1//2(4-x)=-5 log1//3(3-2x)-4 log1//3(10-x)=-3 log2(14-2x)4 log2 3 log7(3-x)=2 log7 4 log2(10-5x)=3 log2 5

Вопрос пользователя:

log8(x+7)=log8(2x-15) log1//2(4-x)=-5 log1//3(3-2x)-4 log1//3(10-x)=-3 log2(14-2x)4 log2 3 log7(3-x)=2 log7 4 log2(10-5x)=3 log2 5

Илюха отвечает:

log8(x+7)=log8(2x-15)

x+7=2x-15

-x=-22

x=22