Вопрос пользователя:
1/x-y * 1/x y * (x/y – y/x)
Илюха отвечает:
1/x-y * 1/x y * (x/y – y/x)=(xy(x-y))/
(xy(x-y))*((x^2-y^2)/ xy)=
(xy*(x-y)*xy)/(
xy(x-y)*(x-y)*(x+y)=xy/(x^2-y^2);
1/x-y * 1/x y * (x/y – y/x)
1/x-y * 1/x y * (x/y – y/x)=(xy(x-y))/
(xy(x-y))*((x^2-y^2)/ xy)=
(xy*(x-y)*xy)/(
xy(x-y)*(x-y)*(x+y)=xy/(x^2-y^2);