Решить дроби x-7 1/3 =12 5/12 5 7/9-x+2 3/4=3 5/12 (3/19+3/4)*1 25/51+2 2/3*9/28

Вопрос от посетителя:

Решить дроби

x-7 1/3 =12 5/12

5 7/9-x+2 3/4=3 5/12

(3/19+3/4)*1 25/51+2 2/3*9/28

$x-7frac{1}{3}=12frac{5}{12}$

$x-frac{22}{3}=frac{149}{12}$

$x=frac{149}{12}+frac{22}{3}$

$x=frac{149+88}{12}$

$x=frac{237}{12}=frac{79}{4}=19frac{3}{4}=19,75$

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$5frac{7}{9}-x+2frac{3}{4}=3frac{5}{12}$

$frac{52}{9}-x+frac{11}{4}=frac{41}{12}$

$frac{52}{9}+frac{11}{4}-frac{41}{12}=x$

$x=frac{52}{9}+frac{11}{4}-frac{41}{12}$

$x=frac{208+99-123}{36}$

$x=frac{184}{36}=frac{46}{9}=5frac{1}{9}$

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$(frac{3}{19}+frac{3}{4})cdot1frac{25}{51}+2frac{2}{3}cdotfrac{9}{28}=2frac{25}{119}$

1) $frac{3}{19}+frac{3}{4}=frac{12+57}{76}=frac{69}{76}$

2) $frac{69}{76}cdot1frac{25}{51}=frac{69}{76}cdotfrac{76}{51}=frac{23}{17}=1frac{6}{17}$

3) $2frac{2}{3}cdotfrac{9}{28}=frac{8}{3}cdotfrac{9}{28}=frac{6}{7}$

4) $1frac{6}{17}+frac{6}{7}=frac{23}{17}+frac{6}{7}=frac{161+102}{119}=frac{263}{119}=2frac{25}{119}$