Вопрос пользователя:
a)x^2+2x-63=0
б)0,9x-3x^2=0
в)2x^2-5x+2=0
г)x^2-2x-6=0
Илюха отвечает:
а) х** + 2х – 63 = 0
х(х + 2) = 63
[x = 63 [x = 63
[x + 2 = 63 [x = 61
б)0.9x – 3x** = 0
3x(0.3 – x) = 0
[3x = 0 [x = 0
[0.3 – x = 0 [x = 0.3
в)2х** – 5х + 2 = 0
х(2х – 5) = -2
[x = -2 [x = -2
[2x -5 = -2 [x = 1.5
г)х** – 2х – 6 = 0
х(х – 2) = 6
[x = 6 [x = 6
[x – 2 = 6 [x = 8