Вопрос для Илюхи:
7(2y-2)-2(3y-3,5)=9
Илюха-Отвечает:
7(2y-2)-2(3y-3,5)=9
14γ – 14 – 6γ + 7 = 9
8γ – 7 = 9
8γ = 16
γ = 16 / 8
γ = 2
проверка
7 (2 * 2 – 2) – 2(3 * 2 – 3,5) = 7 * 2 – 2 * 2,5 = 14 – 5 = 9
7(2y-2)-2(3y-3,5)=9
7(2y-2)-2(3y-3,5)=9
14γ – 14 – 6γ + 7 = 9
8γ – 7 = 9
8γ = 16
γ = 16 / 8
γ = 2
проверка
7 (2 * 2 – 2) – 2(3 * 2 – 3,5) = 7 * 2 – 2 * 2,5 = 14 – 5 = 9