Вопрос от посетителя
(2x-6)(-3x+5)=0 (-2x+3)(6+3x)=0
Отвечает Илюха:
(2x-6)(-3x+5)=0
-6х^2+10х+18х-30=0
-6×2 + 28x – 30 = 0
-6×2 + 28x – 30 = 0
Делим на 2:
-3×2 + 14x – 15 = 0
D = b2 – 4ac
D = 196 – 180 = 16 = 4^2
x1,2 = -b ± √D/2a
x1 = -14 + 4/-6= 10/-6 = 1.6
x2 = -14 – 4/-6 = 18/6= 3
Ответ: x1 = 1.6 ; x2 = 3
(-2x+3)(6+3x)=0
-12x-6x^2+18+9x=0
-6×2 – 3x + 18 = 0
-6×2 – 3x + 18 = 0
Делим на 3:
-2×2 – x + 6 = 0
D = b2 – 4ac
D = 1 + 48 = 49 = 7^2
x 1,2= -b± √D/2a
x1 = 1 + 7/-4=-2
x2 = 1 – 7/-4=1.5
Ответ: x1 = -2 ; x2 = 1.5