Вопрос от посетителя:
2COS(X/2-ПИ/6)=КОРЕНЬ ИЗ 3
Илюха отвечает:
cos(X/2 – π/6) = √ 3 / 2
X/2 – π/6 = ±π/6 + 2 * π * n
X/2 = π/6 ± π/6 + 2 * π * n
X = π/3 ± π/3 + 4 * π * n , n ∈ Z
2COS(X/2-ПИ/6)=КОРЕНЬ ИЗ 3
cos(X/2 – π/6) = √ 3 / 2
X/2 – π/6 = ±π/6 + 2 * π * n
X/2 = π/6 ± π/6 + 2 * π * n
X = π/3 ± π/3 + 4 * π * n , n ∈ Z