Вопрос от посетителя:
(2cosx-1)*(cos2x+1)=0
Илюха отвечает:
1) cos x = 1/2 2) cos 2*x = -1
x = ± π/3 + 2 * π * n 2*x = π + 2 * π * n
x = π/2 + π * n
(2cosx-1)*(cos2x+1)=0
1) cos x = 1/2 2) cos 2*x = -1
x = ± π/3 + 2 * π * n 2*x = π + 2 * π * n
x = π/2 + π * n