Вопрос от посетителя:
16×3-6x-1=0
Илюха отвечает:
16*X³ – 6*X – 1 = (16*X³ + 8*X²) – (8*X² + 6*X + 1) = 8*X²*(2*X+1) – (2*X+1)*(4*X+1) =
= (2*X + 1) * (8*X² – 4*X – 1)
X₁ = – 1/2 X₂₃ = (1 ± √3)/4
16×3-6x-1=0
16*X³ – 6*X – 1 = (16*X³ + 8*X²) – (8*X² + 6*X + 1) = 8*X²*(2*X+1) – (2*X+1)*(4*X+1) =
= (2*X + 1) * (8*X² – 4*X – 1)
X₁ = – 1/2 X₂₃ = (1 ± √3)/4