Вопрос пользователя:
1/2arcsin(sqrt3/2)-2 arccos(-1/2)
Илюха отвечает:
… = (1/2)*(π/3) – 2*(2π/3) = π/6 – 4π/3 = π/6 – 8π/6 = -7π/6
1/2arcsin(sqrt3/2)-2 arccos(-1/2)
… = (1/2)*(π/3) – 2*(2π/3) = π/6 – 4π/3 = π/6 – 8π/6 = -7π/6