решите неравенство :  l2х-4l  < х+1 

Вопрос пользователя:

решите неравенство :  l2х-4l  < х+1 

Илюха отвечает:

-(2х-4)&lt;x+1 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; (2x-4)&lt;x+1

-2x+4&lt;x+1 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;2x-x&lt;4+1

-2x-x&lt;-4+1 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; x&lt;5

-3x&lt;-3

x&lt;1&nbsp;