Вопрос пользователя:
В треугольнике BCD, BC=5,CD=4^2, а угол BDC=45 градусов. Найти sin CBD.
Илюха отвечает:
Дано: треугольник BCD
BC=5
CD=4^2=16
Найти: sinCBD Решение: По теореме синусов: frac{5}{sqrt{2}/2}” title=”frac{BC}{sinBDC}=frac{CD}{sinCBD}” title=”frac{5}{sqrt{2}/2}” title=”frac{BC}{sinBDC}=frac{CD}{sinCBD}” alt=”frac{5}{sqrt{2}/2}” title=”frac{BC}{sinBDC}=frac{CD}{sinCBD}” /> frac{5}{sqrt{2}/2}” alt=”frac{BC}{sinBDC}=frac{CD}{sinCBD}” title=”frac{5}{sqrt{2}/2}” alt=”frac{BC}{sinBDC}=frac{CD}{sinCBD}” alt=”frac{5}{sqrt{2}/2}” alt=”frac{BC}{sinBDC}=frac{CD}{sinCBD}” /> frac{5}{sqrt{2}/2}” />= [tex]frac{16}{sinCBD}” title=”frac{5}{sqrt{2}/2}” />= [tex]frac{16}{sinCBD}” alt=”frac{5}{sqrt{2}/2}” />= [tex]frac{16}{sinCBD}” /> =